How Many Gallons of Water Are Needed to Fill an Olympic-Size Pool?

What is the volume of an olympic-size pool?

An olympic-size pool is 50.0 m long and 25.0 m wide. How many gallons of water (density = 1.0 g/ml) are needed to fill the pool to an average depth of 4.8 ft.?

Answer:

To fill the 50 m long and 25 wide pool to an average depth of 4.8 ft., the needed volume of water is 483,101 gallons

The volume of an olympic-size pool can be calculated by multiplying its length, width, and average depth. In this case, the pool is 50.0 m long, 25.0 m wide, and the average depth is 4.8 ft. Using the formula V = l x w x h, we can plug in the given values: l = 50 m w = 25 m h = 4.8 ft. = 1.463 m V = 50 x 25 x 1.463 V = 1,828.75 m³ Next, we need to convert cubic meters to gallons, where 1 m³ is equal to 264.17 gallons. Therefore: V = 1,828.75 m³ x 264.17 gallons V = 483,101 gallons So, to fill the olympic-size pool to an average depth of 4.8 ft., we would need 483,101 gallons of water. It's incredible how much water a pool of this size can hold, making it perfect for swimming events and competitions during the Olympics!