What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature pressure?
Calculation of Volume of Ammonia Gas
When given the quantity of a gas in moles, it is possible to calculate the volume of the gas by using the Ideal Gas Law equation:
PV = nRT
Where:
P = Pressure
V = Volume
n = Number of moles
R = Ideal Gas Constant
T = Temperature
Given:
Number of moles (n) = 3.50 mol
Standard Temperature (T) = 273 K
Standard Pressure (P) = 1 atm
Ideal Gas Constant (R) = 0.0821 L•atm/mol•K
Let's substitute the given values into the Ideal Gas Law equation:
1 atm * V = 3.50 mol * 0.0821 L•atm/mol•K * 273 K
V = (3.50 * 0.0821 * 273) / 1
V = 78.4 L
Therefore, the volume that 3.50 mol of ammonia gas will occupy at conditions of standard temperature pressure is 78.4 liters.
What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature pressure? C - 78.4L