The World's Best Jumper
How far can the world's best jumper jump?
What is the maximum range of a long jumper with a take-off speed of 9.5 m/s treated as a projectile, under optimal conditions of a 45-degree launch angle and ignoring air resistance?
Answer:
The world's best jumper can jump a maximum range calculated using projectile motion equations. Assuming a take-off speed of 9.5 m/s, a launch angle of 45 degrees, and no air resistance, the maximum range can be determined.
The world's best jumper, under ideal conditions and ignoring air resistance, can achieve a maximum range by treating the jump as a projectile motion problem. In this scenario, the jumper's take-off speed is 9.5 m/s and the launch angle is 45 degrees.
To calculate the maximum range, we can use the projectile motion equation for range: R = (v^2 * sin(2*theta)) / g, where v is the take-off speed (9.5 m/s), theta is the launch angle (45 degrees), and g is the acceleration due to gravity (9.8 m/s^2).
Plugging in these values into the formula, we can calculate the maximum range that the world's best jumper can achieve. The calculated range will give us an estimate of how far the jumper can jump under optimal conditions.