You are called as an expert witness to analyze the following auto accident
Analysis of Auto Accident
a) What was the speed of car A just before the collision?
b) If the speed limit was 35mph, was car A speeding, and if so, by how many miles per hour was it exceeding the speed limit?
c) Explain why we can classify the collision as completely inelastic
d) Calculate the total kinetic energy before and after the collision
a) What was the speed of car A just before the collision? b) If the speed limit was 35mph, was car A speeding, and if so, by how many miles per hour was it exceeding the speed limit? c) Explain why we can classify the collision as completely inelastic d) Calculate the total kinetic energy before and after the collisiona). va=17.23 ๐s or 38.54 mph b). v=38.54 mph and limit is 35 mph c). Completely inelastic d). Eka=192.967 kJ Ekt=76.071 kJ Explanation: ๐๐=1300kg ๐๐=2000kg ๐ฅ๐=7.25m ๐ข๐=0.65 The motion is an inelastic collision so ๐๐*๐ฃ๐+๐๐*๐ฃ๐=(๐๐+๐๐)*๐ฃ๐ The force of the motion is contrarest by the force of friction so F-F๐ข๐=0 F=F๐ข๐ F๐ข๐=๐ข๐*๐*๐ F=m*a a=Fm a=๐น๐ข๐๐ a=๐ข๐*๐ a=0.65*9.89.8๐๐ 2 a=6.39๐๐ 2 Now with the acceleration can find the time and the velocity final that make the distance 7.25m being united ๐ฅ๐=๐ฅ๐+๐ฃ๐*๐ก+2*๐*๐ก2 ๐ฅ๐=0 ๐ฃ๐=0 ๐ฅ๐=2*๐*๐ก2 ๐ก2=๐ฅ๐2*๐ ๐ก=๐ ๐๐๐ก7288๐6.39๐๐ 2 ๐ก=1.06s So the velocity final can be find using this time ๐ฃ๐=๐ฃ๐+๐*๐ก ๐ฃ๐=0 ๐ฃ๐=6.39๐๐ 2*1.06๐ ๐ฃ๐=6.79 ๐๐