The Magnitude of Maximum Magnetic Force on a Pith Ball

Calculation of Maximum Magnetic Force

The magnitude of the maximum magnetic force on a pith ball with a charge of 10nC, moving at 20 m/s perpendicular to a 0.25 T magnetic field, is 5×10^-8 N.

To compute the magnitude of the maximum magnetic force on a pith ball, one can use the equation F = qvBsin(θ), where F is the force, q is the charge, v is the speed, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. Since the velocity is perpendicular to the magnetic field, θ = 90 degrees and sin(90) = 1.

Plugging in the values given, we have F = 10nC × 20m/s × 0.25T. Since 1nC = 1×10^-9 C, the force F = (10×10^-9 C) × 20m/s × 0.25T = 5×10^-8 N.