The Acceleration of a Fighter Jet Catapulted Off an Aircraft Carrier
A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long, what is the acceleration of the jet?
The acceleration of the jet is 28.1 m/s2.
Explanation:
Since the motion of the jet is a uniformly accelerated motion, we can use the following suvat equation:
v2-u2=2as
where:
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have:
u = 0
v = 75 m/s
s = 100 m
Solving for a, we find the acceleration:
a = (v2-u2)/(2s) = (752-0)/(2*100) = 28.1 m/s2
Final answer:
The acceleration of the jet as it is catapulted off the aircraft carrier is found to be approximately 28.125 m/s2, utilizing the third equation of motion.
Explanation:
This question pertains to one-dimensional motion, where the jet travels a known distance at a constant speed from a state of rest. Here, you apply the third equation of motion: final velocity2 = initial velocity2 + 2 * acceleration * distance. The initial velocity in this case is 0 m/s because the jet was at rest, the final velocity is 75 m/s, and the distance is 100 m. Substituting these values into the equation gives: (75 m/s)2 = (0 m/s)2 + 2 * acceleration * 100 m. Solving for acceleration, it comes out to be approximately 28.125 m/s2.
A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long, what is the acceleration of the jet?
The acceleration of the jet is 28.1 m/s^2.