# Rate of Acceleration Calculation for a Hammer Hitting and Bouncing off a Hard Rock

## What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock? The actual bounce takes 0.025 seconds.

What formula should be used to calculate the rate of acceleration in this scenario?

## Answer:

a = 100 m/s^2

## Explanation:

Given that,

Initial velocity, u = -2 m/s

Final velocity, v = 0.5 m/s

Time, t = 0.025 s

We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.

a = (v - u) / t

a = (0.5 - (-2)) / 0.025

a = 100 m/s^2

So, the acceleration of the hammer is 100 m/s^2.

When calculating the rate of acceleration of a hammer hitting and bouncing off a hard rock, we must consider the initial velocity, final velocity, and time taken for the bounce. In this scenario, the hammer's head goes from moving downward at a speed of -2 m/s to moving upward at a speed of 0.5 m/s.

The formula used to calculate acceleration is a = (v - u) / t, where a is acceleration, v is the final velocity, u is the initial velocity, and t is the time taken.

By substituting the given values into the formula, we find that the acceleration of the hammer is 100 m/s^2. This means that the hammer experiences a rapid increase in speed during the bounce off the hard rock.

Understanding the rate of acceleration in such scenarios is crucial for analyzing the impact and dynamics of objects colliding with hard surfaces. It provides valuable insights into the forces involved and the resulting motion of the objects.

By accurately calculating the rate of acceleration, we can further enhance our understanding of physics principles and phenomena in real-world scenarios involving collisions and bounces.