How to Calculate the Magnetic Field Magnitude for a Moving Charge
What information do we need to calculate the magnitude of the magnetic field for a moving charge?
We have a charge of -8.78μC traveling at a speed of 5.59×10^6 m/s in a region of space with a magnetic field. The angle between the velocity of the charge and the field is 50.4°, and a force of magnitude 94×10^-3 N acts on the charge. What is the magnitude of the magnetic field?
Final answer:
The magnitude of the magnetic field can be calculated using the formula F = qvBsinθ. The magnetic field in this case is found to be 1.5 T.
In order to calculate the magnitude of the magnetic field for a moving charge, we can use the formula F = qvBsinθ, where F is the force acting on the charge, q is the charge, v is the speed of the charge, B is the magnetic field, and θ is the angle between the velocity of the charge and the field.
First, we need to rearrange the formula to solve for the magnetic field, B. Plugging in the known values from the problem - charge q = -8.78μC, velocity v = 5.59×10^6 m/s, force F = 94×10^-3 N, and angle θ = 50.4° - we can substitute these values into the formula to find the magnetic field.
By solving the equation with the given values, we can calculate the magnitude of the magnetic field to be 1.5 T.