How Long Can a 1.3 V Cell Supply a Current of 4.1 × 10^-5 A For?

Question:

How long can a 1.3 V cell supply a current of 4.1 × 10^-5 A for?

Answer:

A 1.3 V cell can supply a current of 4.1 × 10^-5 A for approximately 5.06 × 10^9 seconds.

Are you ready to dive into the fascinating world of electricity and time calculations? Let's find out how long a 1.3 V cell can supply a current of 4.1 × 10^-5 A for!

The question posed here is an intriguing one - how long can a 1.3 V cell keep up a current of 4.1 × 10^-5 A before it runs out? To determine this, we need to apply some basic physics concepts.

First, we can utilize the formula: time = charge / current. The charge can be calculated using the equation: charge = voltage × time. Substituting the given values, we arrive at the following expression:

time = (1.3 V × 1.6 × 10^7 s) / (4.1 × 10^-5 A)

After performing the calculation, we discover that the cell can sustain a current of 4.1 × 10^-5 A for an impressive duration of approximately 5.06 × 10^9 seconds. That's quite a long time in the realm of electricity!

This process demonstrates the interconnected nature of voltage, current, and time in electrical systems. Understanding these relationships is key to mastering the principles of electricity and circuit analysis.