# How high is the cliff above the water?

**A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?**

To solve this problem, we can use the equation of motion for an object in free fall:

**s = ut + (1/2)at^2**

Where:

**s**is the total distance traveled (in meters)**u**is the initial velocity (in meters per second)**t**is the time taken (in seconds)**a**is the acceleration due to gravity (approximately 9.8 m/s^2)

Given that the person's mass is 55 kg and the time taken to hit the water is 5.8 seconds, we first calculate the initial velocity using the equation:

**u = gt**

**u = 9.8 * 5.8 = 56.84 m/s**

Now, we can find the height of the cliff above the water by rearranging the equation of motion:

**s = ut + (1/2)at^2**

**s = 56.84 * 5.8 + (1/2) * 9.8 * (5.8)^2 = 328.024 meters**

Therefore, the cliff is **328.024 meters** above the water.

A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?

The cliff is 328.024 meters above the water.