Displacement Vector and Magnitude Calculation

What is the displacement vector of the particle?

Given initial position vector: ri = (0 m)i + (0 m)j + (0 m)k and final position vector: rf = (2 m)i + (3 m)j + (2 m)k, what is the displacement vector of the particle?

Displacement Vector Calculation:

To find the displacement vector of the particle, we subtract the initial position vector from the final position vector.

The particle's initial position vector is ri = (0 m)i + (0 m)j + (0 m)k, and its final position vector is rf = (2 m)i + (3 m)j + (2 m)k.

The displacement vector Δr can be calculated as follows:

Δr = rf - ri = [(2 m) - (0 m)]i + [(3 m) - (0 m)]j + [(2 m) - (0 m)]k

Δr = 2i + 3j + 2k

Therefore, the displacement vector of the particle is Δr = 2i + 3j + 2k.