Determining the Ratio of Resistivity Between Pure Water and Silver

What is the ratio of the resistivity of pure water to silver?

The ratio of the resistivity of pure water to silver is 3 x 10^11.1 : 1.

Understanding Resistivity Ratio Calculation

Resistivity of Silver: Silver is known to be a highly efficient conductor, indicating that its resistivity is low. By referring to a table, we can find the exact value, which is approximately 1.6 x 10^-8 Ω m. Resistivity of Pure Water: On the other hand, pure water is a poor conductor, resulting in a very high resistivity, typically in the range of kilo-ohms per meter (10^3 Ω m). Even without knowing the exact value of pure water's resistivity, we can estimate the ratio between the resistivity of pure water and silver by comparing their orders of magnitude. Calculating the Ratio: We can calculate the ratio by dividing the resistivity of pure water (10^3 Ω m) by the resistivity of silver (10^-8 Ω m). This results in a ratio of approximately 10^11. Therefore, the correct answer to the question is 3 x 10^11.1 : 1. This means that the resistivity of pure water is significantly higher compared to silver, making silver a much better conductor of electricity.
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