Calculating Distance Traveled and Constant Acceleration of a Car
Understanding the Problem
A car accelerates uniformly from rest to a speed of 40.0 mi/h in 12.0 s. We are tasked to find two values: (a) the distance the car travels during this time and (b) the constant acceleration of the car.
Given Data
Initial Position (Xi): 0m
Initial Velocity (Vi): 0m/s
Final Velocity (Vf): 40m/s
Time (t): 12s
Calculations
Distance Traveled (Xf):
Xf = Xi + 1/2(Vi + Vf)t
Xf = 0 + 1/2(0 + 40)12
Xf = 1/2(40)12
Xf = 240m
Constant Acceleration (a):
Vf = Vi + at
40 = 0 + a(12)
40 = 12a
a = 3.33m/s^2
Results
The car travels a distance of 240 meters during this time, and it accelerates at a constant rate of 3.33 m/s^2.
What is the distance the car travels during this time and the constant acceleration of the car? The car travels a distance of 240 meters during this time, and it accelerates at a constant rate of 3.33 m/s^2.