Calculate the Resistance of a Light Bulb

What is the resistance of the light bulb?

A 78.11 volt battery pushes 7.77 amps of current through a light bulb.

Final answer:

The resistance of the light bulb when a 78.11-volt battery pushes 7.77 amps of current through it is calculated using Ohm's law, resulting in a resistance of approximately 10 ohms.

Explanation: The resistance of a light bulb can be calculated using Ohm's law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I). In the given problem, a 78.11-volt battery pushes 7.77 amps of current through a light bulb. To find the resistance, divide the voltage by the current: R = V / I. Therefore, R = 78.11 volts / 7.77 amps. Calculating this gives us a resistance of approximately 10 ohms for the light bulb. When dealing with changes in voltage or current, as long as the resistance remains constant, you can use Ohm's law to determine the new values.

← Electromagnetic waves understanding frequency wavelength and color How to find weight of bolt and number of nuts and bolts that can be made →

More Posts: