What is the period of a sound wave when a tuning fork is vibrating with a frequency of 440 Hz?
The period of a sound wave can be calculated by using the formula:
\[ T = \frac{1}{f} \]
Where \( T \) is the period and \( f \) is the frequency.
Given that the frequency of the tuning fork is 440 Hz, we can calculate the period as follows:
\[ T = \frac{1}{440} \: s = 0.00227\: s \]
Therefore, the period of the sound wave produced by the tuning fork vibrating at 440 Hz is 0.00227 seconds.
Calculation of Period
Period \( T \) is the time taken for one complete cycle of a wave to pass a given point. It is inversely proportional to the frequency of the wave.
In this case, the tuning fork is vibrating at a frequency of 440 Hz. This means that the tuning fork completes 440 cycles or vibrations in one second.
To find the period of the sound wave produced by the tuning fork, we use the formula:
\[ T = \frac{1}{f} \]
Where:
- \( T \) = Period of the sound wave
- \( f \) = Frequency of the sound wave
Substitute the given frequency of 440 Hz into the formula:
\[ T = \frac{1}{440} \: s = 0.00227\: s \]
Therefore, the period of the sound wave produced by the tuning fork vibrating at 440 Hz is 0.00227 seconds.
In conclusion, understanding the relationship between frequency and period is essential in the field of sound waves and vibrations. By knowing the frequency of a sound wave, we can easily calculate its period using the simple formula provided above.