# A Rambunctious Monkey's Bold Leap!

Imagine the thrill of the monkey's daring decision to jump off a cliff with a speed of 6.0 m/s at an angle of 28.0° above the horizontal. The excitement only grew as the monkey landed horizontally 8.00 meters from its starting point.

## The Height of the Cliff:

To determine the height of the cliff, we utilized the concepts of projectile motion. First, we found the horizontal component of the monkey's velocity, which was 5.38 m/s.

The time the monkey spent in the air was calculated to be 1.49 seconds by dividing the horizontal distance traveled by the horizontal velocity. Then, we found the vertical component of the monkey's initial velocity to be 2.80 m/s.

Using the equation of motion s = ut + 0.5at^2 (where s is the vertical displacement, u is the initial vertical velocity, a is the acceleration, and t is time), we computed the height of the cliff to be -5.24 meters. The negative sign signifies the downward displacement due to gravity.

**What an adrenaline-pumping adventure for our brave monkey friend!**