A Circuit Carries a Current of 0.64 A with Resistance of 50.0 Ω

Calculating Voltage in a Circuit

A circuit carries a current of 0.64 A when there is a resistance of 50.0 Ω. The voltage applied to the circuit can be calculated using Ohm's Law. Ohm's Law states that V = I x R, where V is the voltage, I is the current, and R is the resistance. Given that the current is 0.64 A and the resistance is 50.0 Ω, we can substitute these values into the formula: V = 0.64 A x 50.0 Ω V = 32 volts Therefore, the voltage applied to the circuit is 32 volts.

Explanation:

The voltage in the circuit is determined by multiplying the current flowing through the circuit by the resistance of the circuit. In this case, the current is 0.64 A and the resistance is 50.0 Ω. By multiplying these values together, we get the voltage of 32 volts. This means that in order to achieve a current of 0.64 A with a resistance of 50.0 Ω, a voltage of 32 volts needs to be applied to the circuit.

What is the formula used to calculate the voltage in a circuit?

The formula used to calculate the voltage in a circuit is V = I x R, where V is the voltage, I is the current, and R is the resistance.

← Unlocking the mystery of cooking measurements A problem of soccer ball kicked at an angle →

More Posts: