Calculating Acceleration and Distance Traveled

A car accelerates uniformly from rest to a speed of 55.0 mi/h in 14.0 s

The question involves calculating the car's acceleration and distance traveled using kinematic equations, starting from an initial velocity of zero.

Final answer:

The question pertains to high school level Physics and involves calculating the car's acceleration and distance traveled using kinematic equations, starting from an initial velocity of zero.

Explanation:

The subject of the question is Physics, which involves concepts such as acceleration, velocity, and distance. This is a high school level question because it deals with basic kinematic equations that are typically covered in high school physics courses.

To solve the problem mentioned in the question, we would need to calculate the acceleration using the formula:

• a = (vf - vi) / t

Here, 'vf' is the final velocity, 'vi' is the initial velocity, and 't' is the time. Since the car initially starts from rest, vi = 0. Therefore, the acceleration (a) can be calculated as follows:

a = (55.0 mi/h - 0) / 14.0 s

However, it's important to convert the velocity from miles per hour to meters per second before calculating. After finding the acceleration, we can use the kinematic equation:

• x = vi*t + (1/2)*a*t²

to find the distance traveled. The initial velocity (vi) is 0 since the car starts from rest, and 't' is given. This would give us the total distance traveled by the car during the acceleration phase.

What is the question about?

The question relates to calculating the acceleration and distance traveled by a car that accelerates uniformly from rest to a speed of 55.0 mi/h in 14.0 s using basic kinematic equations in Physics.