A High Efficiency Motor Replacement: Reduction in Heat Gain Calculation
Calculation of Reduction in Heat Gain:
Given Data:
- Shaft output power of the motor = 75 hp = (75 × 746) = 55950 W
- Efficiency of the original motor = 91.0% = 0.91
- Efficiency of the high-efficiency motor = 95.4% = 0.954
Firstly, we calculate the electric input given to the original motor:
Efficiency of motor = Output Power / Input Power
0.91 = 55950 W / Input Power
Input Power = 55950 W / 0.91 = 61483.5 W = 61.4835 kW
Next, we calculate the electric input given to the high-efficiency motor:
0.954 = 55950 W / Input Power
Input Power = 55950 W / 0.954 = 58647.79 W = 58.6477 kW
Therefore, the reduction in heat gain due to higher efficiency is:
Reduction in Heat Gain = Power Input Original Motor - Power Input High-Efficiency Motor
Reduction in Heat Gain = 61.4835 kW - 58.6477 kW = 2.8358 kW
Conclusion: The reduction in the heat gain in the room due to the replacement of the motor with a higher efficiency is calculated to be 2.8358 kW. This reduction is a result of the increased efficiency of the high-efficiency motor, which requires less power input to operate at the same output power level. This can lead to cost savings and energy efficiency improvements in the system. If you have any further questions or need clarification, please feel free to ask.