Tetraphosphorus Decoxide Reaction with Water

What is the mass of phosphoric acid produced from the reaction of 10.0 g of tetraphosphorus decoxide with excess water?

1) 13.8 g phosphoric acid

2) 10.0 g phosphoric acid

3) 10.9 g phosphoric acid

4) 40.0 g phosphoric acid

Final Answer:

The mass of phosphoric acid produced from the reaction of 10.0 g of tetraphosphorus decoxide with excess water is 13.8 g.

Tetraphosphorus decoxide reacts with excess water to produce phosphoric acid. The balanced equation for this reaction is:

P4O10 + 6H2O -> 4H3PO4

From the equation, we can see that 1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. To determine the mass of phosphoric acid produced, we need to first calculate the number of moles of P4O10 in 10.0 g.

The molar mass of P4O10 is 283.89 g/mol, so we can calculate the number of moles as follows:

Moles of P4O10 = Mass / Molar Mass

Moles of P4O10 = 10.0 g / 283.89 g/mol

Moles of P4O10 = 0.0353 mol

Since the mole ratio of P4O10 to H3PO4 is 1:4, the number of moles of H3PO4 produced is:

Moles of H3PO4 = Moles of P4O10 x (4/1) = 0.0353 mol x 4 = 0.1412 mol

Finally, the mass of phosphoric acid produced can be calculated using the molar mass of H3PO4:

Mass of H3PO4 = Moles of H3PO4 x Molar Mass

Mass of H3PO4 = 0.1412 mol x 98.0 g/mol = 13.8 g