Understanding Stoichiometry:
Stoichiometry of the reaction:
2 KClO₃ → 2 KCl + 3 O₂
The stoichiometry of a chemical reaction is the calculation of quantitative relationships between reactants and products in a balanced chemical equation. In this case, the equation represents the decomposition of potassium chlorate (KClO₃) into potassium chloride (KCl) and oxygen gas (O₂).
To determine the number of moles of oxygen produced when 2 moles of potassium chlorate (KClO₃) decompose, we utilize the stoichiometry of the reaction:
Calculations:
2 moles KClO₃ → 3 moles O₂
2 moles of KClO₃ decompose, so the question is: How many moles of O₂ are produced?
Using the stoichiometry, we can calculate the answer:
2 moles of KClO₃ x (3/2) = 3 moles of O₂
Therefore, when 2 moles of potassium chlorate decompose, 3 moles of oxygen gas are produced.
Hope this explanation helps clarify the concept of stoichiometry in this reaction!
How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?
The answer is 3.
Explanation: 2 mol of potassium chlorate x (3/2) = 3.