How Many Gold Atoms Are in a 0.330 Ounce, 18K Gold Bracelet?

How many gold atoms are in a 0.330 ounce, 18K gold bracelet?

The number of gold atoms in a 0.330 ounce, 18K gold bracelet would be 2.12 x 10^22 atoms of gold.

1. How many grams is 0.330 ounce?

2. How much gold is in a 0.330 ounce, 18K gold bracelet?

3. How many moles are in 6.93 grams of gold?

4. How many atoms are in 0.0352 moles of gold?

Answer:

The number of gold atoms in a 0.330 ounce, 18K gold bracelet is 2.12 x 10^22 atoms of gold.

To calculate the number of gold atoms in a 0.330 ounce, 18K gold bracelet, we need to follow the given data:

1. 1 ounce = 28 grams

Therefore, 0.330 ounce = 0.330 x 28 = 9.24 grams

2. 18K gold is 75% gold by mass:

18K gold = 75% gold = 9.24 x 0.75 = 6.93 grams

So, a 0.330-ounce, 18K gold bracelet contains 6.93 grams of actual gold.

3. Mole of 6.93 gold = 6.93/196.967 = 0.0352 mol

1 mole = 6.022 x 10^23 atoms

4. 0.0352 mole = 0.0352 x 6.022 x 10^23 = 2.12 x 10^22 atoms

Therefore, a 0.330-ounce, 18K gold bracelet contains 2.12 x 10^22 atoms of gold.

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