Gas Volume Calculation at Different Temperatures and Pressures

What is the initial volume of a sample of N2 gas at a pressure of 1.50 atm and a temperature of 23 ∘C?

The initial volume of the N2 gas sample is 13.0 L.

What volume, in liters, will the gas occupy at 3.50 atm and 281 ∘C?

What is the new volume of the gas at the increased pressure and temperature?

Answer:

The new volume of the N2 gas at 3.50 atm and 281 ∘C would be calculated using the Ideal Gas Law formula.

The given initial volume of the N2 gas sample is 13.0 L at a pressure of 1.50 atm and a temperature of 23 ∘C. To find the new volume of the gas when the pressure changes to 3.50 atm and the temperature increases to 281 ∘C, we need to apply the Ideal Gas Law.

The Ideal Gas Law formula is represented by the equation pV = nRT, where p is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature. When pressure and temperature change, the volume of the gas also changes.

To calculate the new volume of the N2 gas, we can rearrange the Ideal Gas Law formula and substitute the given values into the equation. By using the relation V2 = (P1V1T2)/(P2T1), we can determine the new volume of the gas at the altered pressure and temperature.

Remember to convert the temperature to Kelvin before performing the calculation. The conversion from Celsius to Kelvin is done by adding 273.15 to the Celsius temperature. In this case, 23 ∘C is equivalent to 296 K and 281 ∘C is equivalent to 554 K.

By plugging in the initial volume, pressure, and temperature values (13.0 L, 1.50 atm, 296 K) and the new pressure and temperature values (3.50 atm, 554 K) into the formula, you can find the new volume of the N2 gas sample under the changed conditions.

For further information and examples on the Ideal Gas Law, you can explore additional resources on gas laws and calculations.