Determining Atom Composition of Alloy with Pb and Sn

What is the composition, in atom percent, of an alloy that consists of 4.5 wt% Pb and 95.5 wt% Sn?

Can you determine the atom percent composition of an alloy made up of 4.5 wt% Pb and 95.5 wt% Sn?

Composition of the Alloy:

The composition, in atom percent, of the alloy is 2.18% Pb and 80.44% Sn.

When determining the atom composition of an alloy with 4.5 wt% Pb and 95.5 wt% Sn, it is important to convert the weight percentages to atomic percentages by dividing the weight percent by the atomic weight of each element.

First, calculate the atomic weight of Pb and Sn:

Atomic weight of Pb = 207.19 g/mol

Atomic weight of Sn = 118.71 g/mol

Next, convert the given weight percentages to atomic percentages:

Percent by weight (wt%) of Pb = 4.5%

Atomic percent (at%) of Pb = (4.5 / 207.19) × 100 = 0.0218 × 100 = 2.18%

Percent by weight (wt%) of Sn = 95.5%

Atomic percent (at%) of Sn = (95.5 / 118.71) × 100 = 0.8044 × 100 = 80.44%

Therefore, the composition, in atom percent, of the alloy is 2.18% Pb and 80.44% Sn. This means that the alloy is composed of approximately 2.18% Pb atoms and 80.44% Sn atoms in terms of atom percent.