Density of Unknown Gas in a Sample Calculation

What is the density of the unknown gas in the 0.149 mol sample?

A) 0.050 g/L B) 0.149 g/L C) 3.00 g/L D) 0.447 g/L

Final Answer:

The density of the unknown gas in the 0.149 mol sample is D) 0.447 g/L.

Let's solve this problem together! The density of a gas can be determined using the ideal gas law, which relates the number of moles, pressure, volume, and temperature of a gas to its density. In this case, we are given the number of moles (0.149 mol) and asked to find the density.

To find the density of the unknown gas, we can use the formula density = n/V, where n is the number of moles and V is the volume. Using the ideal gas law formula PV = nRT, we can rearrange it to solve for V as V = (nRT)/P.

Since the question does not provide information about the pressure, we can assume it to be constant. Therefore, the formula simplifies to density = (nRT)/V. Density is inversely proportional to volume, meaning that as the volume decreases, the density increases.

Looking at the options provided, D) 0.447 g/L corresponds to the highest density, which makes sense because with the same number of moles in a smaller volume, the density will be higher. Therefore, the correct answer is D) 0.447 g/L.