Chemistry Question: Neutralization Reaction Calculation

In a neutralization reaction between a 35.0 mL volume of ammonia (NH3) household cleaner and 53.75 mL of 0.300 M HNO₃, what is the number of moles of HNO₃ involved? To find the number of moles of HNO₃ involved in this reaction, we can use the formula: Number of moles = Molarity × Volume (in liters)

When referring to a neutralization reaction like the one described, it is important to understand the concept of molarity. Molarity is a concentration unit that is defined as the number of moles of solute per liter of solution. In this case, the molarity of the HNO₃ solution is given as 0.300 M, meaning there are 0.300 moles of HNO₃ in one liter of the solution.

Given that the volume of HNO₃ used in the reaction is 53.75 mL, which is equal to 0.05375 L (since 1 L = 1000 mL), we can calculate the number of moles of HNO₃ involved:

Number of moles of HNO₃ = Molarity × Volume

Number of moles of HNO₃ = 0.300 M × 0.05375 L

Number of moles of HNO₃ = 0.016125 moles

Therefore, in the neutralization reaction between the ammonia household cleaner and the HNO₃ solution, 0.016125 moles of HNO₃ are involved.

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