Chemistry Conversion Challenge

16 May 2023

How many moles of Ca(OH)2 are present in 75.0 g of Ca(OH)2? (MM = 74.09 g/mol)

Answer:

To find out how many moles of Ca(OH)2 are in 75.0 g, we need to divide the given mass by the molar mass. The result is 1.01 moles.

When solving problems involving converting mass to moles, the key step is to divide the given mass by the molar mass of the compound. In this case, the molar mass of Ca(OH)2 is 74.09 g/mol. By dividing 75.0 g by 74.09 g/mol, we can determine that there are 1.01 moles of Ca(OH)2 present in 75.0 g of the compound.

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How many moles of Ca(OH)2 are present in 75.0 g of Ca(OH)2? (MM = 74.09 g/mol)

Answer:

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