Chemical Reaction Molarity Calculation

What was the molarity of the HCl solution?

Given the balanced chemical equation:

2HCl + Ca(OH)2 ---> CaCl2 + 2H2O

Vhcl = 1 L

Vcaoh2 = 2 L

Ccaoh2 = 1.5 mol/L.


The molarity of the HCl solution was 6 mol/L.

Reflecting on the molarity calculation for the HCl solution in the given chemical reaction, it is crucial to understand the stoichiometry involved in the reaction. The balanced chemical equation provided allows us to determine the relationship between the reactants and products involved in the reaction.

In this particular case, the reaction between 2 moles of HCl and 1 mole of Ca(OH)2 produces 2 moles of H2O and 1 mole of CaCl2. By using the volume and concentration information provided for Ca(OH)2, we were able to calculate the molarity of the HCl solution using the formula:

Chcl = ((Ccaoh2 * Vcaoh2) * (2 mol HCl/1 mol Ca(OH)2)) / Vhcl

Substituting the values into the formula, we arrive at a molarity of 6 mol/L for the HCl solution. This calculation highlights the importance of understanding the stoichiometry of a chemical reaction and how it relates to concentration calculations in solutions.

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