Chemical Reaction Fun Facts!

Let's Dive into Chemistry!

1) What is the free energy of the reaction at STP?

2) Can you calculate the equilibrium constant of the reaction at 25°C?

3) Will an increase in the partial pressure of H2O favor the reaction?

4) How do we calculate the P_H2O at equilibrium when the pressure of H2 and O2 are known?

Answer:

We cannot calculate the free energy of the reaction at STP or the equilibrium constant of the reaction at 25°C based on the given information. We also cannot determine whether an increase in the partial pressure of H2O will favor the reaction or calculate the partial pressure of H2O at equilibrium.

Explanation:

To calculate the free energy of the reaction at STP, we need to use the equation ∆G = ∆H - T∆S. However, the given information does not provide the entropy change (∆S) for the reaction. Therefore, we cannot calculate the free energy of the reaction at STP.

To calculate the equilibrium constant of the reaction at 25°C, we can use the equation K = e^(-∆G/RT), where R is the gas constant (8.314 J/mol·K) and T is the temperature in Kelvin. However, we do not have the value of ∆G for the reaction. Therefore, we cannot calculate the equilibrium constant of the reaction at 25°C.

An increase in the partial pressure of H2O (P_H2O) will favor the reaction if the stoichiometric coefficient of H2O in the balanced equation is positive. In this case, the balanced equation is not provided, so we cannot determine whether an increase in P_H2O will favor the reaction.

To calculate the partial pressure of H2O (P_H2O) at equilibrium, we need to know the equilibrium constant (K) and the partial pressures of H2 (P_H2) and O2 (P_O2). However, the equilibrium constant and the partial pressures of H2 and O2 are not provided. Therefore, we cannot calculate the partial pressure of H2O at equilibrium.