Calculating Number of Potassium Atoms in K2S Compound

Calculation Process:

Step 1: Find the moles of K2S

Moles = mass / molar mass = 235 g / 110 g/mol = 2.136 moles

Step 2: Multiply 2.136 moles by the number of K atoms in K2S

2.136 moles × 2 = 4.272 moles

Step 3: Use Avogadro's law to determine the number of K atoms

1 mole = 6.02 x 10^23 atoms

4.272 moles = ? atoms

By cross multiplication, (4.272 moles × 6.02 x10^23 atoms) / 1 mole = 2.57 x 10^24 atoms

Therefore, the number of atoms of potassium in 235 grams of K2S is calculated to be 2.57 x 10^24 atoms.

In order to calculate the number of atoms of K in 235 grams of K2S, the number of moles of K2S needs to be calculated. Moles of K2S = mass / molar mass = 235 g / 110 g/mol = 2.136 moles. Since the number of atoms in the K2S molecule is two, multiply the number of moles of K2S by 2 to get 4.272 moles. Using Avogadro's law, the number of atoms of K in the compound is found to be 2.57 x 10^24 atoms.