Calculate the Volume of a Gas at Standard Temperature
Explanation:
Given data:
Initial temperature = 9°C (9+273 = 282 K)
Initial volume of gas = 6.17 L
Final volume of gas = ?
Final temperature = standard = 273 K
Solution:
Formula:
The Charles Law will be applied to solve the given problem. According to this law, 'the volume of a given amount of gas is directly proportional to its temperature at a constant number of moles and pressure'.
Mathematical expression:
Vâ/Tâ = Vâ/Tâ
Vâ = Initial volume
Tâ = Initial temperature
Vâ = Final volume
Tâ = Final temperature
Now we will put the values in the formula:
Vâ/Tâ = Vâ/Tâ
Vâ = VâTâ/Tâ
Vâ = 6.17 L Ã 273 K / 282 K
Vâ = 1684.41 L.K / 282 K
Vâ = 5.97 L