Calculate the Mass of Sodium Needed to Produce Hydrogen Gas at STP
What mass of sodium is required to yield 22.4 L of hydrogen gas at STP?
Given: 22.4 L of hydrogen gas at STP
The atomic mass of sodium is 22.99 u
Answer:
To calculate the mass of sodium needed to produce 22.4 L of hydrogen gas at STP, we need to follow these steps:
Step 1: Determine the Moles of Hydrogen Gas
Since 22.4 L of anything at STP is equal to one mole, we already have one mole of hydrogen gas (H2).
Step 2: Find the Moles of Sodium Required
From the chemical equation 2Na + 2H2O -> 2NaOH + H2, we know that 2 moles of sodium (Na) yield 1 mole of hydrogen gas (H2).
Therefore, to produce one mole of H2, we need 2 moles of Na.
Step 3: Calculate the Mass of Sodium
Now, we can calculate the mass of sodium required using the formula:
Mass = Moles x Molar Mass
Mass of Na = 2 moles x molar mass of Na
Mass of Na = 2 moles x 22.99 g/mol = 45.98 g
Therefore, 46.0 grams of sodium (Na) is required to yield 22.4 L of hydrogen gas at STP.