What is the volume of H2S needed to neutralize 45mL of NH2-?
The volume of H2S needed to neutralize 45mL of NH2- is 0.053 L.
A neutralization reaction, in which an acid and a base react to form water and salt.The reaction between H2S and NH2- is a neutralization reaction. The balanced equation for the reaction is:
H2S(aq) + NH2-(aq) → NH4HS(aq)
We know that the concentration of H2S is 1.2 M and the concentration of NH2- is 0.80 M, and we are trying to find the volume of H2S needed to neutralize 45mL of NH2-.
The number of moles of H2S can be calculated by using the formula:
moles = molarity x volume
The volume of H2S needed to neutralize 45mL of NH2- is equal to the number of moles of NH2- in 45mL, divided by the concentration of H2S.
moles of NH2- = 0.080 L * 0.80 mol/L = 0.064 mol
volume = moles of NH2- / molarity of H2S
volume = 0.064 mol / 1.2 mol/L = 0.053 L
Therefore, the volume of H2S needed to neutralize 45mL of NH2- is 0.053 L.
Understanding Neutralization Reactions
Neutralization reactions occur when an acid and a base combine to form water and a salt. These reactions are essential in chemistry and play a vital role in various applications. In a neutralization reaction, the acid donates a proton (H+) to the base, forming water (H2O) and a salt.
The Calculation Process
When calculating the volume of H2S needed to neutralize NH2-, we follow a step-by-step process. First, we determine the concentrations of the acid (H2S) and base (NH2-) solutions. In this case, the concentration of H2S is 1.2 M, and the concentration of NH2- is 0.80 M.
Next, we convert the volume of NH2- from milliliters to liters and calculate the number of moles of NH2- present in the solution. This is done using the formula: moles = molarity x volume.
Then, we find the volume of H2S required to neutralize the NH2- solution by dividing the number of moles of NH2- by the molarity of H2S.
By following this calculation method, we determine that the volume of H2S needed to neutralize 45mL of NH2- is 0.053 L.
For further insights into neutralization reactions and related concepts, you can explore additional resources on chemical reactions and stoichiometry. Understanding these principles is crucial for mastering chemistry and its practical applications.